# How to find the largest value in a list and its index with python ?

To find the largest number in a list with python, a solution is to use the function max():

````>>> l = [4,7,9,4,1,6,9]`
`>>> max(l)`
`9`
```

which returns 9 here. To find the index, there is the function index(), example:

````>>> l.index(max(l))`
`2`
```

Note: this function only returns the first index found. To find all the indexes of a maximum value (if there is several occurrences of the maximum value), we can do like in this example:

````>>> indices = [i for i, x in enumerate(l) if x == max(l)]`
`>>> indices`
`[2, 6]`
```

To find if there is several times the max value in the list, a solution is to use the python function count(), example:

````>>> l = [4,7,9,4,1,6,9]`
`>>> max_value = max(l)`
`>>> max_value `
`9`
`>>> l.count(max_value)`
`2`
```

it is then possible to write a simple function that returns the index(es):

````>>> def get_indexes_max_value(l):`
`...     max_value = max(l)`
`...     if l.count(max_value) > 1:`
`...             return [i for i, x in enumerate(l) if x == max(l)]`
`...     else:`
`...             return l.index(max(l))`
`... `
`>>> get_indexes_max_value(l)`
`[2, 6]`
```